Y^3-9y^2+27y-27=0

Solution for Y^3-9y^2+27y-27=0 equation:

^3-9Y^2+27Y-27=0

We add all the numbers together, and all the variables

-9Y^2+27Y=0

a = -9; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-9)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-9}=\frac{-54}{-18}
=+3
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-9}=\frac{0}{-18}
=0
$